Question

( find the cube of
(21^2)/7

Answer 1

Answer:

$\text{The cube of }\frac{21^2}{7}\text{ is }250047$

Step-by-step explanation:

Given the expression

$\frac{21^2}{7}$

$\text{we have to find its cube i.e }(\frac{21^2}{7})^3$

$(\frac{21^2}{7})^3$

$\text{As }(\frac{a}{b})^x=\frac{x^x}{b^x}$

∴ $(\frac{21^2}{7})^3=\frac{(21^2)^3}{7^3}$

$\text{Also, }(x^a)^b=x^{ab}$

$(\frac{21^2}{7})^3=\frac{21^2\times 3}{7^3}=\frac{21^6}{7^3}=\frac{85766121}{343}=250047$

$\text{Hence, the cube of }\frac{21^2}{7}\text{ is }250047$

Answer 2

($3^{6} * 7^{3}$) or 250047

Step-by-step explanation:

Given that,

$(\frac{21^2}{7} )^{3}$

To find,

Cube of $(\frac{21^2}{7} )^{3}$

Procedure:

$(\frac{21^2}{7} )^{3}$

= [(21)^2]^3 ÷ 7^3

= 21^6 ÷ 7^3

= (21 * 21 * 21 * 21^3) ÷ (7 * 7 * 7)

= (3 * 3 * 3 * 21^3)

= 3^3 * (7 * 3)^3

= 3^6 * 7^3

∵ The cube of (21^2)/7 would be (3^6 * 7^3) or 250047.

Learn more: Find the cube

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