find the cube of 2a+1/2a
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2a+1/2a=2a/2a + 1/2a[in binomial divided by monomial,each term of binomaial is to be divided by monomial]
ans=1 + 1/2a
their cube by identity [a+b]3 =a3+b3+3a2b+3ab2
let1/2a be a 1 be b
their cube=1/2a cube+1 cube+3*1*1/2a*1+3*1*1/2a*1/2a
=1/8a3+1+3/2a+3/4a2
is the answer
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ans=1 + 1/2a
their cube by identity [a+b]3 =a3+b3+3a2b+3ab2
let1/2a be a 1 be b
their cube=1/2a cube+1 cube+3*1*1/2a*1+3*1*1/2a*1/2a
=1/8a3+1+3/2a+3/4a2
is the answer
please mark as brainliest
Intogenius:
thanks
is it not brainliest
please mark as brainliest
it is wrong ans ; 8a^3+6a+3/2a+1/8a^3
aboveis answer
whats the question.i took it as]2a+1 ] / 2a
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