Question

find the cube of 2a - 1/a
a is unequal to 0​

Answer 1

Answer:

since the eigenvalue of matrix A is zero

(I−A) is invertible we have

(I−A)(I+A+A

2

)=I−A

3

=I−0=I

(I−A)(I+A+A

2

)=I

∴I+A+A

2

=(I−A)

−1

Step-by-step explanation:

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Answer 2

Answer:

PLEASE SEE THE ATTACHED IMAGE

Step-by-step explanation:

• QUESTION : $(2a - \frac{1}{a})^{3}$

• CONCEPT USED :

$(\frac{x}{y} )^{n} \ = \frac{x^{n} }{y^{n}}$

(a - b)³ = a³ - b³ - 3ab(a - b)

(a + b)³ = a³ + b³ + 3ab(a + b)

• SOLUTION :

PLEASE SEE THE ATTACHED IMAGE.

• SIMILAR QUESTIONS

https://brainly.in/question/25671546

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