Question

find the cube of
2a+ I/2a (a is not equal to 0)​

Answer 1

Answer:

8a³+6a+(3/2a)+(1/8a³)

Step-by-step explanation:

[2a + (1/2a) ]³

= [4a²+1]³ / (2a)³

= [ (4a²)³ + 1³ + 3(4a²)(1)(4a²+1) ]  / 8a³

= [64a^6 + 1 + 48a^4 + 12a²] / 8a³

= 8a³+6a+(3/2a)+(1/8a³)