Question

find the cube of 2x+3/x

Answer 1

(2x+3/x)^3
=8x^3+27/x^3+36x+54/x

Answer 2

Answer :

Now,

${(2x + \frac{3}{x}) }^{3} \\ \\ = {(2x)}^{3} + (3 \times {(2x)}^{2} \times \frac{3}{x} ) + (3 \times 2x \times {( \frac{3}{x} )}^{2} ) + { (\frac{3}{x} )}^{3} \\ \\ = 8 {x}^{3} + (3 \times 4 {x}^{2} \times \frac{3}{x} ) + (3 \times 2x \times \frac{9}{ {x}^{2} } ) + \frac{27}{ {x}^{3} } \\ \\ = 8 {x}^{3} + 36x + \frac{54}{x} + \frac{27}{ {x}^{3} }$

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