Find the cube of (2x + 3y)
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Answer:
(2x + 3y)³
= (2x)³+(3y)³+3(2x)²(3y)+3(2x)(3y)²
=8x³+ 27y³+ 36x²y+ 54xy²
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ANSWER
We know that the identity is (a+b) 3 =a 3 +b 3 +3a 2 b+3ab 2
Therefore,
(2x+3y) 3 =(2x) 3+(3y) 3 +(3×(2x) 2
×3y)+(3×2x×(3y) 2 )=8x 3 +27y 3 +(9y×4x 2 )+(6x×9y 2)
=8x 3 +27y 3 +36x 2y+54xy 2.
Hence, (2x+y) 3 =8x 3 +27y 3 +36x 2y+54xy 2.
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We know that the identity is (a+b) 3 =a 3 +b 3 +3a 2 b+3ab 2
Therefore,
(2x+3y) 3 =(2x) 3+(3y) 3 +(3×(2x) 2
×3y)+(3×2x×(3y) 2 )=8x 3 +27y 3 +(9y×4x 2 )+(6x×9y 2)
=8x 3 +27y 3 +36x 2y+54xy 2.
Hence, (2x+y) 3 =8x 3 +27y 3 +36x 2y+54xy 2.
Hope this helps u
Plz mark me as the brainliest
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