Question

find the cube of 3/x -2/x²
Whoever will ans this I will gie 10 rs in paytm​

Answer 1

Step-by-step explanation:

3/x -2/x²

3x²-2x/x³

x(3x-2)/x³

(3x-2)/x²

[(3x-2)/x²] [(3x-2)/x²] [(3x-2)/x²]

3x-2 X 3x-2 X 3x-2/ x². x².x²

3x(3x-2)-2(3x-2) X 3x-2/x⁶

9x²-6x -6x +4 X 3x-2/x⁶

9x²-12x+4(3x-2)/x⁶

3x(9x²-12x+4)-2(9x²-12x+4)/x⁶

27x³-36x²+12x-18x²+24x-8/x⁶

27x³-54x²+36x-8/x⁶

x(27x²-54x+36)-8/x⁶

27x²-54x+36-8/x⁵