find the cube of 35 using identity:(a+b)^3=a^3 +b^3+3a^2b+3ab^2 a=20,b=3
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please check the question it should be wrong..
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Answer:
(a+b)³=a³+3ab+3ab²+b³
Step-by-step explanation:
LHS=(a+b)^{3}
=(a+b)(a+b)^{2}
=(a+b)(a^{2}+2ab+b^{2})
/* By algebraic identity:
\boxed {(x+y)^{2}=x^{2}+2xy+y^{2}}*/
=a(a^{2}+2ab+b^{2})+b(a^{2}+2ab+b^{2})
= a^{3}+2a^{2}b+ab^{2}+a^{2}b+2ab^{2}+b^{3}
=a^{3}+(2+1)a^{2}b+(1+2)ab^{2}+b^{3}
= a^{3}+3a^{2}b+3ab^{2}+b^{3}
=$RHS$
Therefore,
(a+b)³=a³+3ab+3ab²+b³
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