Question

Find the cube of (3x+2)
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Answer 1

Answer:

${(3x + 2)}^{3}$

${(x+ y)}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2}$

${(3x)}^{3} + {2}^{3} + 3 {(3x)}^{2} 2 + 3 \times 3x \times {2}^{2}$

$27 {x}^{3} + 8 + 54 {x}^{2} + 36x$

$27 {x}^{3} + 54 {x}^{2} + 36x + 8$

Answer 2

Answer:

${(3x + 2)}^{3} \\ {(x + y}^{3} = {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2 } \\ = {(3x + 2)}^{3} = 27 {x }^{3} + 8 + 54 {x}^{2} + 36x \\ = 27 {x}^{3} + 54 {x}^{2} + 36x + 8$