Question

find the cube of 4-1/3x​

Answer 1

$\sf{(4 - \dfrac{1}{3x})^{3}}$

=> (4)³ - (1/3x)³ - 3(4)²(1/3x) - 3(4)(1/3x)²

=> 64 - (1/27x³) - (16/x) + (4/3x²)

Answer 2

Answer:

(a+b)³ = a³ + b³ + 3ab(a+b)

(4 - 1/3x)³ = (4)³ - (1/3x)³ -3*4*1/3x(4 - 1/3x)

= 64 - 1/27x³ - 4/x(4 - 1/3x)

= 64 - 1/27x³ - 16/x + 4/3x²