Math, asked by ritikgupta649, 5 months ago

find the cube of (4y+ 3z)​

Answers

Answered by prithapaul35
3

Answer:

(4y+3z)³

=(4y)³+(3z)³+36yz(4y+3z)

64y³+27z³+144y²z+108yz²

It is done by (a+b)³=a³+b³+3ab(a+b)

Answered by sargunjune2008
1

Answer:

(4y+3z)³

=(4y)³+(3z)³+36yz(4y+3z)

64y³+27z³+144y²z+108yz²

It is done by (a+b)³=a³+b³+3ab(a+b)

Step-by-step explanation:

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