find the cube of (4y+ 3z)
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Answered by
3
Answer:
(4y+3z)³
=(4y)³+(3z)³+36yz(4y+3z)
64y³+27z³+144y²z+108yz²
It is done by (a+b)³=a³+b³+3ab(a+b)
Answered by
1
Answer:
(4y+3z)³
=(4y)³+(3z)³+36yz(4y+3z)
64y³+27z³+144y²z+108yz²
It is done by (a+b)³=a³+b³+3ab(a+b)
Step-by-step explanation:
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