Question

find the cube of 7 by the sum of consecutive odd number​

Answer 1

Answer:

let the first odd integer be x.

therefore , x+x+2+x+4+x+6+x+8+x+10+x+12=7^3

x+x+2+x+4+x+6+x+8+x+10+x+12= 343

=> 7x + 42 = 343

7x=301

x=301/7

x=43

therefore , 43+45+47+49+51+53+55= 343

or, 43+45+47+49+51+53+55=7^3

Step-by-step explanation:

let the first odd integer be x.

therefore , x+x+2+x+4+x+6+x+8+x+10+x+12=7^3

x+x+2+x+4+x+6+x+8+x+10+x+12= 343

=> 7x + 42 = 343

7x=301

x=301/7

x=43

therefore , 43+45+47+49+51+53+55= 343

or, 43+45+47+49+51+53+55=7^3