find the cube of 729 by factor method
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Answered by
1
Answer:
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Step-by-step explanation:
Step 1: Find the prime factors of 729
729 = 3 × 3 × 3 × 3 × 3 × 3
Step 2: Clearly, 729 is a perfect cube. Here we will be using laws of exponents.
729 = 36 [am × an = am+n]
729 = [32]3 [(am)n = amn]
729 = 93
Step 3: Now, we will apply cube root to both the sides of the above expression to take out the factor as a single term, which is in cubes.
3√729 = 3√(93)
So, here the cube root is cancelled by the cube of 9.
Hence, 3√729 = 9
Answered by
5
Answer:
Here is your answer mate
Step-by-step explanation:
You have to you prime factorisation for this
3 | 729
3 |243
3 |81
3 |27
3 |9
3 |3
|1
So = 3×3×3×3×3×3
=3^3 × 3^3
=(3×3)^3
9 cube
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