Question

FIND THE CUBE OF 9/-17

Answer 1

Answer:

$( \frac{9}{ - 17} )^{3} = \frac{9 \times 9 \times 9}{( - 17) \times ( - 17) \times ( - 17)} = \frac{729}{ - 4913 }$

Answer 2

Cubing a number means multiplying the same number three times.

Example 2³ is 2 × 2 × 2 = 8

Now coming to your question

$\bigg(\dfrac{9}{-17}\bigg)^3\\ \\ = \bigg(\dfrac{-9}{17}\bigg)^3 \\ \\ = \dfrac{-9}{17} \times \dfrac{-9}{17} \times \dfrac{-9}{17} \\ \\ = \dfrac{-729}{4913}$

So the cube of $\bf{\dfrac{9}{-17} }$ is $\bf{\dfrac{-729}{4913}}$ .