Question

find the cube of (9/2 - b/3 )​

Answer 1

Step-by-step explanation:

(a-b)^3 = a^3 +b^3 + 3a^2b -3ab^2

(9/2)^3 + (b/3)^3 + 3(9/2)^2(b/3) - 3(9/2)(b/3)^2

729/8 + b^3/27 + 81b/2 - 3b^2/2

b^3/27 - 3b^2/2 + 81b/2 +729/8