find the cube of each of the following binomial expressions [tex]1/x + y/3
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I don't know that's answer
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Cube of the given binomial expression will be:
( 1/x + y/3 ) ^3 = 1/x^3 + y^3/27 + 3× 1/x^2 .y/3+ 3 1/x y^2 /9 . ANS.
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