Question

Find the cube of each of the following binomial expressions$3/x -2/x^{2}$

Answer 1

Answer:

( 3/x - 2/x² )³

= (3/x)³ - (2/x²)³ - 3×(3/x)×(2/x²) [(3/x) - (2/x²)

= 27/x³ - 8/x⁶ - 18/x³ [(3/x) - (2/x²)]

= 27/x³ - 8/x⁶ - 54/x⁴ - 36/x⁵

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