Question

Find the cube
of = p²+q²​

Answer 1

$\rm \large \bold{Hola! }$

• GiveN :

$\mapsto \sf \: {p}^{2} + {q}^{2}$

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• To FienD :

$\mapsto \sf \: {( {p}^{2} + {q}^{2} ) }^{3} = {?}$

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• SolutioN :

$\mapsto \: \sf ({ {p}^{2} + {q}^{2} })^{3}$

$\sf \implies \: { ({p}^{2}) }^{3} + { ({q}^{2} )}^{3} + 3 {p}^{2} {q}^{2} ( {p} + {q} )$

$\sf \implies \: {p}^{6} + {q}^{6} + 3 {p}^{2} {q}^{2} ( {p} + {q})$

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