Question

find the cube of
$- 3 \frac{4}{9}$
​

Answer 1

Answer:

$cub e\: of \: - 3 \frac{4}{9}$

${( - 3 \frac{4}{9} )}^{3}$

${ (\frac{(9 \times ( - 3)) + 4}{9}) }^{3}$

${ (\frac{ - 27}{9} )}^{3}$

${( - 3)}^{3}$

$- 27$