find the cube of the 105 by identities
Answers
Answered by
9
(105)³
=> (100+5)³
Using identity,
(a +b)³=a³+b³+3ab(a+b)
=> (100+5)³=(100)³+(5)³+3(500)(105)
=> (105)³ = 1000000+125+1500(105)
=> (105)³ = 1000000+125 + 157500
=> (105)³ = 1157625
=> (100+5)³
Using identity,
(a +b)³=a³+b³+3ab(a+b)
=> (100+5)³=(100)³+(5)³+3(500)(105)
=> (105)³ = 1000000+125+1500(105)
=> (105)³ = 1000000+125 + 157500
=> (105)³ = 1157625
sushant2505:
Hi Abhi ! 100³ ≠ 10000 but 100³ = 1000000 :-)
Hii.... Wait bro
(-:
In next step also ... :-)
and Answer is 1157625 :-)
Hahaha.... Edited
Answer ?
Didn't understand
Answer is 1157625 .. not 1175625
Hehehe.... Is baar :- thanks
Answered by
5
Hi,
Here is your answer !
_____________________________
We know that the identity
( a + b )³ = a³ + b³ + 3ab(a + b)
Now, using above identity
105³ = (100 + 5)³
= 100³ + 5³ + 3×100×5 (100 + 5)
= 1000000 + 125 + 1500 × 105
= 1000000 + 125 + 157500
= 1157625
Hence,
105³ = 1157625
Here is your answer !
_____________________________
We know that the identity
( a + b )³ = a³ + b³ + 3ab(a + b)
Now, using above identity
105³ = (100 + 5)³
= 100³ + 5³ + 3×100×5 (100 + 5)
= 1000000 + 125 + 1500 × 105
= 1000000 + 125 + 157500
= 1157625
Hence,
105³ = 1157625
Thanks Saniya ;-)
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