Question

Find the cube of the sum of the 1st ten natural number​

Answer 1

In general: the sum of the first n natural numbers is (n)(n+1)/2. the sum of the first n natural squares is (n)(n+1)(2n+1)/6. the sum of the first n natural cubes is the SQUARE of the sum of the first n natural numbers: [(n)(n+1)/2]²