Question

Find the cube of x-1/x+y ,( x does not equal to 0)

Answer 1

Answer:Given expression,

 x/y+y/x=-1

 =>x²+y²/xy=-1                      [ Since, L.C.M. of x and y =xy   ]

 =>x²+y²=-xy

 =>x²+y²+xy=0    ..................( Equation i )

 Now,

  formula of a³-b³=(a-b)(a²+ab+b²)

  applying this formula  to find x³+y³

 =>x³-y³=(x-y)(x²+xy+y²)

 By equation i, value of (x²+xy+y²)=0

=>x³-y³=(x-y)*0

=>x³-y³=0

     (Solved)

Step-by-step explanation:

Answer 2

Answer:

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