find the cube of :x/2 + y/3
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Answer:
let
x/2 = p and y/3 = q
(p+q)³ = p³ + q³ + 3p²q + 3pq²
= x³/8 + y³/27 + 3x²y/12 + 3xy²/18
or x³/8 + y³/27 + x²y/4 + xy²/6
(further solving wouldn't make any difference because variables are different)
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