Question

find the cube root of (1)76.25 (2)37.62 (3)458 (4)732

Answer 1

Holla ! Here is u r Ans>
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Cube root of 76.25
$= \sqrt[3]{76.25}$

$= \sqrt[3]{ \frac{305}{4} } = \frac{ \sqrt[3]{305} }{ \sqrt[3]{4} }$

$= \frac{ \sqrt[3]{305 \times 4 {}^{2} } }{4} = \frac{ \sqrt[3]{305 \times 16} }{4}$

$= \frac{2 \sqrt[3]{305 \times 2} }{4}$

$\frac{ \sqrt[3]{305 \times 2} }{2}$

$= \frac{ \sqrt[3]{610} }{2}$
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Cube root of 37.62
$= \sqrt[3]{37.62}$

$= \sqrt[3]{ \frac{1881}{50} } = \frac{ \sqrt[3]{1881} }{ \sqrt[3]{50} }$

$= \frac{ \sqrt[3]{1881 \times 50 {}^{2} } }{50} = \frac{ \sqrt[3]{1881 \times 2500} }{50}$

$= \frac{5 \sqrt[3]{1881 \times 20} }{50} = \frac{5 \sqrt[3]{1881 \times 20} }{10}$

$= \frac{ \sqrt[3]{37620} }{10}$
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Cube root of 458
$= \sqrt[3]{458}$

$\sqrt[3]{458} = congruent \: 7.70824$
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Cube root of 732
$\sqrt[3]{732} = congruent \: 9.01233$
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# Be Brainly
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Answer 2

Step-by-step explanation:

Holla ! Here is u r Ans>

==================================================

Cube root of 76.25

= \sqrt[3]{76.25}=

3

76.25

= \sqrt[3]{ \frac{305}{4} } = \frac{ \sqrt[3]{305} }{ \sqrt[3]{4} }=

3

4

305

=

3

4

3

305

= \frac{ \sqrt[3]{305 \times 4 {}^{2} } }{4} = \frac{ \sqrt[3]{305 \times 16} }{4}=

4

3

305×4

2

=

4

3

305×16

= \frac{2 \sqrt[3]{305 \times 2} }{4}=

4

2

3

305×2

\frac{ \sqrt[3]{305 \times 2} }{2}

2

3

305×2

= \frac{ \sqrt[3]{610} }{2}=

2

3

610

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Cube root of 37.62

= \sqrt[3]{37.62}=

3

37.62

= \sqrt[3]{ \frac{1881}{50} } = \frac{ \sqrt[3]{1881} }{ \sqrt[3]{50} }=

3

50

1881

=

3

50

3

1881

= \frac{ \sqrt[3]{1881 \times 50 {}^{2} } }{50} = \frac{ \sqrt[3]{1881 \times 2500} }{50}=

50

3

1881×50

2

=

50

3

1881×2500

= \frac{5 \sqrt[3]{1881 \times 20} }{50} = \frac{5 \sqrt[3]{1881 \times 20} }{10}=

50

5

3

1881×20

=

10

5

3

1881×20

= \frac{ \sqrt[3]{37620} }{10}=

10

3

37620

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Cube root of 458

= \sqrt[3]{458}=

3

458

\sqrt[3]{458} = congruent \: 7.70824

3

458

=congruent7.70824

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Cube root of 732

\sqrt[3]{732} = < br / > congruent \: 9.01233

3

732

=<br/>congruent9.01233

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# Be Brainly

^__^