find the cube root of 1728 by prime factorization msthod
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Answered by
247
Step-by-step explanation:
1728 = 2 × 2 × 2 × 2 × 2 × 2 ×3 × 3 × 3
Multiply all these and the result will be answer for cube root of 1728 i.e. 2 × 2 × 3 = 12
So, finally the cube root of 1728 = 12.
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Answered by
109
Answer: The answer is 12.
Step-by-step explanation:
I have explained here
We should assume a three time repeating digit in the factors as one.
As here by assuming each three as one we will get 2,2 and 3.
Now we should multiply these numbers.
2 x 2 x 3 = 12
which is the cube root of 1728 as mentioned.
CHECK :
12 x 12 x 12 = 1728
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