Math, asked by Balbisingh, 1 year ago

find the cube root of 19683

Answers

Answered by Muskan1101

Hii..
Here is your answer..

Solution:-
$= > 3 \sqrt{19683} \\ = > 27$
Hope It helps you...✌️✌️✌️

Answered by Anonymous

19683 is said to be a perfect cube because 27 x 27 x 27 is equal to 19683. Since 19683 is a whole number, it is a perfect cube. The nearest previous perfect cube is 17576 and the nearest next perfect cube is 21952 .

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