Math, asked by 1169966, 2 months ago

Find the cube root of:
-19683/85184

Answers

Answered by 161811annikagrace

1

Answer:

The principal, real, root of:

19683−−−−−√3196833

=27=27

Step-by-step explanation:

alĺ roots:

2727

−13.5+23.3826859i−13.5+23.3826859i

−13.5−23.3826859i−13.5−23.3826859i

19683 is a perfect cube

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