Question

find the cube root of -27 and show that the sum of roots is zero​

Answer 1

Let the cube root of 1 be x √(1) = x x^3 = 1 x^3 - 1 = 0 (x - 1 ) (x^2 + x + 1 ) = 0 x - 1 = 0,x^2 + x + 1 = 0 x = 1, x^2 + x + 1 = 0 x = -1±√(1

Answer 2

Answer:

-3...... is the cube root of -27