find the cube root of 512 plss answer with full steps .
shazi16:
hello
Answers
Answered by
5
The prime factors of 512
= 2x 256
= 2x2x128
= 2x2x2x64
= 2x2x2x2x32
= 2x2x2x2x2x16
=2x2x2x2x2x2x8
=2x2x2x2x2x2x2x4
=2x2x2x2x2x2x2x2x2
=2^3 x 2^3 x 2^3
= 8 x 8 x 8
The cube root of 512 is 8.
Ans : 8.
= 2x 256
= 2x2x128
= 2x2x2x64
= 2x2x2x2x32
= 2x2x2x2x2x16
=2x2x2x2x2x2x8
=2x2x2x2x2x2x2x4
=2x2x2x2x2x2x2x2x2
=2^3 x 2^3 x 2^3
= 8 x 8 x 8
The cube root of 512 is 8.
Ans : 8.
Answered by
15
Here is your solution
Firstly,
we factorise 512
512 =2×2×2×2×2×2×2×2×2
512=2^3×2^3×2^3
Now we get
512 = 8 x 8 x 8 = 8³
Therefore,
The cube root of 512 = ³√512 = 8
Firstly,
we factorise 512
512 =2×2×2×2×2×2×2×2×2
512=2^3×2^3×2^3
Now we get
512 = 8 x 8 x 8 = 8³
Therefore,
The cube root of 512 = ³√512 = 8
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