Math, asked by Nishika20, 10 months ago

find the cube root of a)74088,b)2.744 simplify a) (3^0+4^-1)*2^2, b) (2^5/2^8)^5*2^5

Answers

Answered by banbajaj78
1

Answer:

Step-by-step explanation:

1 a) cube root of 74088

by prime factorization = 74088=2x2x2x3x3x3x7x7x7

so cube root = 2x3x7= 42

by same method cube root of  1 b) 2.744 = 1.4

2a) 5(3^0+4^-1)*2^2

=5(1 +1/4) x 4

5 x 5/4 * 4

=25

2b) (2^5/2^8)^5*2^5

(32/256)^5 * 32

(1/16)^5 * 32

=0.0009765625

Answered by NishanthReddy5647
0

27000=2×2×2 ×3×3×3×5×5×5 ... Simplify 381×64125 ... If 216=2a3b, then find the value of a+b.

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