Question

Find the cube root of each of the following numbers : - 250047, in prime factorization.

Answer 1

250047=3×3×3×3×3×3×7×7×7

$250047=3 {}^{6} \times 7 {}^{3}$

Taking cuberoot

$\therefore \: \sqrt[3]{250047} = \sqrt[3]{3 {}^{6} \times {7}^{3} }$

$= {3}^{2} \times 7$

$= 63$

Hence 63 is the cube root of 250047

Answer 2

Answer:

we cannot factorise this number