Question

Find the cube root of each of the following numbers by prime factorisation method.

1)64
2)512
3)10648
4)27000
5)15625
6)13824
7)110592
8)46656
9)175616
10)91125​

Answer 1

(i) 64 (ii) 512 (iii) 10648 (iv) 27000 (v) 15625 (vi) 13824 ... (vi) 13824 (vii) 110592 (viii) 46656 (ix) 175616 (x) 91125 .

Answer 2

Answer:

1)  64 = 2 x 2 x 2 x 2 x 2 x 2

= 2³ x 2³

³√64 =   2×2=4

2) 512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

= 2³x 2³ x 2³

³√512 =   2×2×2=8

3)  10648 = 2 x 2 x 2 x 11 x 11 x 11

= 2³ x 11³

³√10648 =   2×11=22

4)  27000 = 2 x 2 x 2 x 3 x 3 x 3 x 5 x 5 x 5

= 2³ x 3³ x 5³

³√27000 =   2×3×5=30

5) 15625 = 5 x 5 x 5 x 5 x 5 x 5

= 5³x 5³

³15625 =   5×5=25

6) 13824 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3

= 2³x 2³ x 2³ x 3³

³√13824 =   2×2×2×3=24

7) 110592 = 2³ x 2³ x 2³ x 2³ x 3³

³√110592 =   2×2×2×2×3=48

8) 46656 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3

= 2³ x 2³ x 3³x 3³

³√46656 =   2×2×3×3=36

9) 175616 = 2³x 2³ x 2³ x 7³

³√175616 =   2×2×2×7=56

10) 91125 = 5³ x 3³ x 3³

³√91125 =   5×3×3=45

PLEASE MARK THIS ANSWER BRAINLIEST