Question

Find the cube root of

$a} \: 10 + 6 \sqrt{3}$
$b} \: 38 \sqrt{14 \: } - 100 \sqrt{2}$
Please solve these questions______☺️

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Answer 1

Answer:

1.1000+216√27

2.56012-10,00,000√8

Answer 2

Question:

$1. \: 10 + 6 \sqrt{3}$

$2. \: 38 \sqrt{14} + 100 \sqrt{2}$

Step-by-step explanation:

$1. \: 10 + 6 \sqrt{3}$

$\implies 10 + 6(1.732)$

$\implies 10 + 10.392$

$\implies \boxed{20.392}$

$2. \: 38 \sqrt{14} + 100 \sqrt{2}$

$\implies 38(3.741) + 100(1.414)$

$\implies 142.182981 + 141.4$

$\implies \boxed{283.582981}$

$\bigstar \sqrt{14} = 3.741$

$\bigstar \sqrt{2} = 1.414$

$\bigstar \sqrt{3} = 1.732$