find the cube root of the following 1728 with process.
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The cube root of 1728 is the number which when multiplied by itself three times gives the product as 1728. Since 1728 can be expressed as 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3. Therefore, the cube root of 1728 = ∛(2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3) = 12.
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The value of the cube root of 1728 is 12. It is the real solution of the equation x3 = 1728. The cube root of 1728 is expressed as ∛1728 in radical form and as (1728)⅓ or (1728)0.33 in the exponent form. As the cube root of 1728 is a whole number, 1728 is a perfect cube.
Cube root of 1728: 12
Cube root of 1728 in exponential form: (1728)⅓
Cube root of 1728 in radical form: ∛1728
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