Question

find the cube root of the following number the by prime factorszation method. (i).343 (ii).729 (iii).1331 (iv).2744​

Answer 1

Answer:

$\sqrt[3]{343} = 7$

$\sqrt[3]{729} = 9$

$\sqrt[3]{1331} = 11$

Answer 2

Answer:

(i) 343 = 7×7×7. Cube root = 7

(ii) 729 = 3×3×3×3×3×3. Cube root = 3×3 = 9

(iii) 1331 = 11×11×11. Cube root = 11

(iv) 2744 = 2×2×2×7×7×7. Cube root = 2×7 = 14