Question

Find the cube root of the following numbers by prime factorisation method: 216 proper solution​

Answer 1

Prime Factors of 216 = 2 x 2 x 2 x 3 × 3 x 3

After cutting the common numbers , we get = 2*3 = 6

So ∛216 = 6.

KEEP SMILING! KEEP SHINING!!

Answer 2

Solution :

$\bigstar$ Firstly,we get L.C.M method of 216 :

$\begin{array}{r|l} 2 & 216 \\ \cline{2-2} 2 & 108 \\ \cline{2-2} 2 & 54 \\ \cline{2-2} 3 & 27\\ \cline{2-2} 3 & 9 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1\end{array}}$

Prime factorization of 216 = 2 × 2 × 2 × 3 × 3 × 3

$\longrightarrow\sf{3\sqrt{2\times 2\times 2\times 3\times 3\times 3}} \\\\\longrightarrow\sf{3\sqrt{(2)^{3} \times (3)^{3} } }\\\\\longrightarrow\sf{2\times 3}\\\\\longrightarrow\bf{6}$

Thus,

The cube root of 216 will be 6 .