find the cube root of the following prime factorization
(i) 5832
(ii) 1728
(iii) 216000
(iv) 21952
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rahul077:
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Answers
Answered by
11
(¡)5832
=>2×2×2×3×3×3×3×3×3
=> 18 ×18×18
(¡¡) 1728
=>2×2×2×2×2×2×3×3×3
=> 12 ×12×12
(¡¡¡) 216000
=>2×2×2×2×2×2×3×3×3×5×5×5
=> 60×60×60
(iv) 21952
=>2×2×2×2×2×2×7×7×7
=> 28×28×28
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Answered by
3
hi mate,
Answer:
(¡)5832
=>2×2×2×3×3×3×3×3×3
=> 18 ×18×18
=>(18)³
(¡¡) 1728
=>2×2×2×2×2×2×3×3×3
=> 12 ×12×12
=>(12)³
(¡¡¡) 216000
=>2×2×2×2×2×2×3×3×3×5×5×5
=> 60×60×60
=>(60)³
(iv) 21952
=>2×2×2×2×2×2×7×7×7
=> 28×28×28
=>(28)³
i hope it helps you.
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