Math, asked by dvsheeba1978, 8 months ago

Find the cube root of the rational numbers 10648/12167

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Answered by Anonymous
2

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Answered by sanchitachauhan241
3

\huge\red\star{{Hello}}

Let us consider the following rational number

\frac{10648}{12167}

Now,

\sqrt[3]{\frac{10648}{12167}}

\frac{\sqrt[3]{10648}}{\sqrt[3]{12167}} (:[\sqrt[3]{\frac{a}{b}}= \frac{\sqrt[3]{a}}{\sqrt[3]{b}}

Cube roots by factors

On factorising 10648 into prime factors, we get:

\[10648=\left\{2\times 2\times 2\times \right\}\times\left\{11 \times 11\times 11 \right \}

On grouping the factors in triplets of equal factors, we get :

\[1068 =\left\{2 \times 2 \times 2 \times \right\}\times \left \{11 \times 11 \times 11 \times\right\}

Now, taking one factors from each triple, we get

\sqrt[3]{12167}} =  \ 2 \times 11 =22

Also factorising 12167 into prime factor, we get

12167 = {\23 \times 23 \times 23}}

Now getting one factor from the triple, we get:

\sqrt[3]{12167} =23

Now,

\sqrt[3]\frac{10648}{12167}

= \frac{\sqrt[3]{10648}}{\sqrt[3]{12167}}

= \frac{22}{23}

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