Find the cubes of the following expression
a) 2x+3y
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Answer:
We know that the identity is (a+b)
3
=a
3
+b
3
+3a
2
b+3ab
2
Therefore,
(2x+3y)
3
=(2x)
3
+(3y)
3
+(3×(2x)
2
×3y)+(3×2x×(3y)
2
)=8x
3
+27y
3
+(9y×4x
2
)+(6x×9y
2
)
=8x
3
+27y
3
+36x
2
y+54xy
2
Hence, (2x+y)
3
=8x
3
+27y
3
+36x
2
y+54xy
2
.
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