find the cubic equation two of whose roots are 1-i and 5
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Answer:
- x³ - x² + x - 1 = 0
Step-by-step explanation:
Question,
Find the cubic equation whose roots are 1,i.
Solution,
If i is one root, the other root will be -i
So, the roots are:-
- 1
- i
- -1
So, the equation will be,
=> (x - 1)(x + i)(x - i) = 0
=> (x - 1)(x² - i²) = 0
=> x³ + x - x² - 1 = 0
∴ x³ - x² + x - 1 = 0
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