Question

find the cubic equation whose roots are a-d, a, a+d​

Answer 1

Answer:

Step-by-step explanation:

roots are = x = (a-d) , a , (a + d )

so, equation = (x- a +d) (x-a) (x-a-d)

     = (x² - ax +dx -ax + a² - ad) ( x-a-d)

     = x³ - ax² +dx² -ax² -adx -ax² +a²x -adx+a²x- a³ +a²d -dx² +adx -d²x +adx          

       -a²d +ad²

     =x³-ax² -ax² -ax² + dx²-dx² -adx -adx +adx+adx +a²x +a²x +a²d -d²x- a²d +ad²- a³

     = x³-3ax² +2a²x -d²x +ad² -a³

hope it helps;)

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