find the cubic equation whose roots are the cubes of the roots of x^3+ax^2+bx+c=0 a, b, c belongs to real numbers
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if the roots of the given equation are p,q,r then the roots of the required equations are p^3,q^3,r^3.
let y=x^3 then x=y^(1/3)
replace x in the original equation by x^(1/3)
(x^(1/3))^3+a(x^(1/3))^2+b(x^(1/3))+c=0
x+ax^(2/3)+bx^(1/3)+c=0
let y=x^3 then x=y^(1/3)
replace x in the original equation by x^(1/3)
(x^(1/3))^3+a(x^(1/3))^2+b(x^(1/3))+c=0
x+ax^(2/3)+bx^(1/3)+c=0
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