Find the cubic poly nominal with the sum ,sum of the product of its zeroes taken two at a time , and the product of its zeroes is 2,-7,-14 respectively
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Let the polynomial be ax³ + bx² + cx + d and the zeroes be α, β and γ.
Then,
(i) α + β + γ = -(-2)/1 = 2
(ii) αβ + βγ + γα = -7 = -7/1 = c/a
(iii) αβγ = -14 = -14/1 = -d/a
∴ a = 1, b = -2, c = -7 and d = 14.
So, one cubic polynomial which satisfy the given conditions will be : x³ - 2x² - 7x + 14.
Hope this helps!
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