find the cubic polynomial in "x" which when divided by x-1,x-2 and x-3 leaves remainder 11,22,and 39 respectively
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We know that the remainder when f(x) is divided by x−α is f(α). If we say that
f(x)=ax2+bx+c
then we have
a×12+b×1+ca+b+ca×22+b×2+c4a+2b+ca×32+b×3+c9a+3b+c=11=11=22=22=37=37(1)(2)(3)
We then have 3 equations in 3 unknowns so we can solve these for a,b,c: (2)−(1):
3a+b=11(4)
(3)−(2):
5a+b=15(5)
(5)−(4):
2a=4a=2
From (4):
3×2+b=11b=5
From (1):
2+5+c=11c=4
And therefore, our quadratic is:
f(x)=2x2+5x+4
hope it helped uhh...
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