find the cubic polynomial whose 3 zeroes are 3,-1 and -1/3
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Answer:
Step-by-step explanation:
a=3 ,b=-1 ,c=-1/3
a+b+c = 5/3
ab+bc+ca = 3+1/3-1 = 7/3
abc = 1
f(x)= k[x³-x²(a+b+c)+x(ab+bc+ca)-abc]
k[x³-(5/3)x²+(7/3)x-1]
put k=3
f(x) = 3x³-5x²+7x-3
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