Question

find the cubic polynomial whose 3 zeroes are 3,-1 and -1/3​

Answer 1

Answer:

Step-by-step explanation:

a=3 ,b=-1 ,c=-1/3

a+b+c = 5/3

ab+bc+ca = 3+1/3-1 = 7/3

abc = 1

f(x)= k[x³-x²(a+b+c)+x(ab+bc+ca)-abc]

       k[x³-(5/3)x²+(7/3)x-1]

put k=3

f(x) = 3x³-5x²+7x-3