find the cubic polynomial whose zeroes are1/2,1,-3
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Answer:
2x²-3x²-8x+3
Step-by-step explanation:
the factors are (x-1/2),(x-1) and (x+3)
(x-½) (x-1) (x+3) = 0
(x-½) (x²-3x-x-3) = 0
(x-½) (x²-2x+3) = 0
x³+2x²-3x-½x²-x+3/5 = 0
x³+3\2x²-4x+3\2 = 0
2x³+3x²-8x+3 = 0
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