find the cubic polynomial whose zeros are -1,2,3
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The required cubic polynomial is x³-4x²+x+6
1) According to fundamental theorem of algebra, A polynomial of form f(x)= (x-a)(x-b)(x-c) would have zeroes as a,b,c
2) Given the zeroes of cubic polynomial are -1,2,3
3) Considering these as values of a,b,c and substitutig in the equation of theorem
4) f(x)= (x-(-1))(x-2)(x-3)
f(x)= (x+1)(x-2)(x-3)
5)Multiplying the terms together
f(x)= (x²-x-2)(x-3)
f(x) = (x³-4x²+x+6)
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