Find the cubic polynomial whose zeros are - 2 - 3 and -1
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Answered by
65
Answer:
x³ + 6x² + 11x + 6
Step-by-step explanation:
Let the zeroes of the cubic polynomial be α, β and γ respectively. Thus,
- α = (-2)
- β = (-3)
- γ = (-1)
Sum of roots = α + β + γ
⇒ (-2) + (-3) + (-1)
⇒ - 2 - 3 - 1
⇒ - 6
Sum of products of roots = αβ + βγ + γα
⇒ (-2)(-3) + (-3)(-1) + (-1)(-2)
⇒ 6 + 3 + 2
⇒ 11
Product of roots = αβγ
⇒ (-2) * (-3) * (-1)
⇒ 6 * (-1)
⇒ - 6
Now, cubic polynomial is given by -
= x³ - (α + β + γ)x² + (αβ + βγ + γα)x - αβγ
= x³ - (-6)x² + 11x - (-6)
= x³ + 6x² + 11x + 6
Hence, the required cubic polynomial is x³ + 6x² + 11x + 6.
Answered by
3
Answer:
answer : x³ + 6x² +11x +6
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