Question

find the cubic polynomial whose zeros are -5,4 and 3​

Answer 1

Step-by-step explanation:

alpha + beta + gamma = -b/a

(-5)+4+3 = -b/a

2 = -b/a

Here b = -2 and a = 1

(alpha*beta) + (beta*gamma) + (gamma*alpha) = c/a

(-5*4) + (4*3) + (3*-5) = c/a

(-20)+12+(-15)=c/a

-23=c/a

Here c = -23 and a = 1

alpha*beta*gamma = -d/a

(-5)*4*3 = -d/a

-60 = -d/a

Here d = 60 and a = 1

form of cubic polynomial is ax^3+bx^2+cx+d

so 1x^3 + (-2)x^2 + (-23)x + 60

x^3 -2x^2 -23 +60

is the required polynomial