Find the cubic polynomial with the sum of itsome zeroes , sum of the product of its zeroes taken two at a time and product of its zeroes as 0,-7 and -6 respectively
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given,alpha+beta+gama=0=-b/a
alpha×beta+beta×gama+gama=×alpha=-7=c/a
alpha×beta×gama=-6=-d/a
so,-b/a=0/1;-d/a=-6/1 and c/a=-7/1 so comparing both sides,
a=1,b=0,c=-7 and d=6
now polynomial p(x)=x^3+0x^2-7x+6=x^3-7x+6
thank u, hope it helps!
alpha×beta+beta×gama+gama=×alpha=-7=c/a
alpha×beta×gama=-6=-d/a
so,-b/a=0/1;-d/a=-6/1 and c/a=-7/1 so comparing both sides,
a=1,b=0,c=-7 and d=6
now polynomial p(x)=x^3+0x^2-7x+6=x^3-7x+6
thank u, hope it helps!
HimanshiKankane:
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